Question

utilizando o processo algébrico de Bhaskara , determine as raízes das equações do 2 ° grau no conjunto de números reais a) x²_10x+9 = 0 b) x²+x-6=0

Answer 1

$a)~x^2-10x+9=0,~onde: \\ \\ a=1,~b=-10,~c=9 \\ \\ \Delta~=b^2-4.a.c \\ \Delta~=(-10)^2-4.1.9 \\ \Delta~=100-36 \\ \Delta~=64$

$x= \frac{-b\pm \sqrt{\Delta~}}{2.a} \\ x= \frac{10\pm \sqrt{64}}{2.1} \\ x= \frac{10\pm8}{2}$

$x'= \frac{10+8}{2}= \frac{18}{2}=9 \\ x''= \frac{10-8}{2}= \frac{2}{2}=1$


$b)~x^2+x-6=0,~onde: \\ \\ a=1,~b=1,~c=-6 \\ \\ \Delta~=b^2-4.a.c \\ \Delta~=1^2-4.1.(-6) \\ \Delta~=1+24 \\ \Delta~=25$

$x= \frac{-b\pm \sqrt{\Delta~}}{2.a} \\ x= \frac{-1\pm \sqrt{25}}{2.1} \\ x= \frac{-1\pm5}{2}$

$x'= \frac{-1+5}{2}= \frac{4}{2}=2 \\ x''= \frac{-1-5}{2}= \frac{-6}{2}=-3$

Answer 2

soluçao de A) x1-9.x2-1