Question

Me ajudem , por favor

Answer 1

${4}^{2x} . {2}^{y} = 1 \\ {2}^{4x}. {2}^{y} = {2}^{0} \\ {2}^{4x + y} = {2}^{0} \\ 4x + y = 0$

${2}^{x - y} = 16 \\ {2}^{x - y} = {2}^{4} \\ x - y = 4$

{4x+y=0

+{x-y=4

5x=4

x=4/5

y=-4x

y=-4.(4/5)=-16/5

S={4/5,-16/5}