Question

Sendo f(x)=x² - 3x + 1, calcule:

a) f(0)

b) f(x)=0​

Answer 1

a-)f(0)= 0²-3•0+1

f(0)= 1

b-) f(x)= 0

x²-3x+1= 0

∆=b²-4ac

∆=9-4

∆=5

-b±√∆/2a

3±√5/2

x1= 3+√5/2

x2= 3-√5/2