Question

$(2x - 3) \times (x - 8) = 34$

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Answer 1

Explicação passo-a-passo:

$(2x - 3) \times (x - 8) = 34$

$2 {x}^{2} - 16x - 3x + 24 = 34$

$2 {x}^{2} - 19x - 10 = 0$

Delta=-19²-4*2*-10

Delta=361+80

Delta=441, raiz de delta=21

$x1 = \frac{19 + 21}{2 \times 2} = \frac{40}{4} = 10$

$x2 = \frac{19 - 21}{2 \times 2} = \frac{ - 2}{4} = \frac{ - 1}{2} = - 0.5$

Bons Estudos Jovem!!

Answer 2

Resposta:

$(2x-3)(x-8)=34\\ \\ 2x^2-16x-3x+24=34\\ \\ 2x^2-19x+24-34=0\\ \\ 2x^2-19x-10=0\\ \\ a=2\\ b=-19\\ c=-10\\ \\ \Delta=b^2-4ac\\ \Delta=(-19)^2-4(2)(-10)\\ \Delta=361+80\\ \Delta=441\\ \\ x={-b\pm\sqrt{\Delta} \over2a}={-(-19)\pm\sqrt{441} \over2(2)}={19\pm21\over4}\\ \\ x_1={19-21\over4}=-{2\over4}=-{1\over2}\\ \\ x_2={19+21\over4}={40\over4}=10\\ \\ S=\{-{1\over2},10\}$