Question

Calcule o ∆ de x²÷2-x+12÷3=2x÷1.

Answer 1

x²/2 – x + 12/3 = 2x/1

x²/2 – x + 4 = 2x

x²/2 – x – 2x + 4 = 0

x²/2 – 3x + 4 = 0

delta = (–3)² – 4 • 1/2 • 4

delta = 9 – 8

delta = 1

x = (3 ± 1)/(2/2)

x = 3 ± 1

x1 = 3 + 1 = 4

x2 = 3 – 1 = 2

Answer 2

Assunto: equaçao do segundo grau.

• sendo equaçao:

 x²/2 - x + 12/3 = 2x/1

• reescreve:

 x²/2 - 3x + 4 = 0

 x² - 6x + 8 = 0

• os coeficientes:

 a = 1

 b = -6

 c = 8

• o valor do delta:

 d = 36 - 32 = 4

• as raizes

 x1 = (6 + 2)/2 = 8/2 = 4

 x2 = (6 - 2)/2 = 4/2 = 2