Question

Fatorial .Simplifique as expressões. b) (n+4)! sob (n+2)!+(n+3)!

Answer 1

$\frac{(n + 4)!}{(n + 2)! + (n + 3)!} = \\ \frac{(n + 4)(n + 3)(n + 2)!}{(n + 2)! + (n + 3)(n + 2)!} = \\ \frac{(n + 4)(n + 3)(n + 2)!}{(n + 2)! ( n + 4)} = n + 3$

a expressão é igual a n+3