Question

(3x-2)(x-5)(2-x)x>0​

Answer 1

$(3x-2)(x-5)x>0\\(3x^{2} -15x-2x+10)x>0\\3x^{3} -17x^{2} +10x>0\\\\3p^{2} -17p+10=0$

Δ = b² - 4.a.c

Δ = (-17)² - 4 . 3 . 10

Δ = 289 - 4. 3 . 10

Δ = 169

p = (-b +- √Δ)/2a

p' = -(-17 + √169)/2.3     p'' = (--17 - √169)/2.3

p' = 30 / 6                      p'' = 4 / 6

p' = 5      

Cálculo de x:

$x^{2} = p\\x^{2} =5\\x=+-\sqrt{5} \\\\\\x^{2} =p\\x^{2} =4/6\\x=2/\sqrt{6}$