Question

calcule, se existir: a) 3pi/2 ; b) tg 0 ; c) tg 5pi/3 ; d) tg 3pi/4

Answer 1

a) 3π/2 = 3 . 180/2 = 3 . 90 = 270º
b) tg 0º = 0
c) tg 5π/3 = tg 5 . 180/3 = tg 5 . 60 = tg 300 --> 360 - 300 = 60...
... tg 300 = - tg 60 = -√3
d) tg 3π/4 = tg 3 . 180/4 = tg 3 . 45 = tg 135 --> 180 - 135 = 45
tg 45 = 1 --> tg 135 = -1