Question

Sabendo que log2 = 0,
3010 e
log 3 = 0,4771 o valor de log ³√12 é​

Answer 1

Resposta:

Letra B

Explicação passo-a-passo:

log∛12 = log12¹'³ = 1/3 . log 3.4 = 1/3 log3 + 1/3 log4 = 1/3log3 + 1/3log2² = 1/3log3 + 1/3.2log2 = 1/3 log3 + 2/3log2 = 0,4771/3 + 2.0,3010/3 = 0,1590 + 0,2006 = 0,3596

Answer 2

Resposta:

$log\sqrt[3]{12} =log12^{{1\over3}}={1\over3}log12\\ \\ {1\over3}log12={1\over3}log4\times3=\\ \\ {1\over3}log4\times3={1\over3}(log2+log2+log3)=\\ \\ {1\over3}(0,3010+0,3010+0,4771)=\\ \\ {1\over3}(1,0791)=\\ \\ 1,0791\div3=0,3597$