Question

log x = 4 e log y = 24, então log
$( \sqrt[3]{ {x}^{2} \times y } )$
é:?
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Answer 1

Resposta:

Explicação passo-a-passo:

$log\sqrt[3]{x^{2}.y}=log({x^{2}.y})^{\frac{1}{3}}=\frac{1}{3}.log({x^{2}.y})=\\\\\\=\frac{1}{3}.(logx^{2}+logy)=\frac{1}{3}.(2.logx+logy)=\\\\=\frac{1}{3}.(2.4+24)=\frac{1}{3}.(8+24)=\dfrac{32}{3}$