• Matéria: Matemática
  • Autor: karoll586
  • Perguntado 7 anos atrás

Se
 \sqrt[3]{a }  = 2
então o valor da expressão
 -  \sqrt[3]{ {a}^{2} }  +   \sqrt[3]{ \frac{1}{a} }
é:

(A)
  \frac{ - 7}{2}
(B)
 \frac{ - 5}{2}
(C)
 - 1
(D)
 \frac{1}{2}
(E)
 \frac{7}{2}

Respostas

respondido por: GeBEfte
1

-\sqrt[3]{a^2}~+~\sqrt[3]{\frac{1}{a}}~=\\\\\\=~-\left(\sqrt[3]{a}\,\right)^2~+~\dfrac{\sqrt[3]{1}}{\sqrt[3]{a}}\\\\\\=~-\left(2\right)^2~+~\frac{1}{2}\\\\\\=~-4~+~\frac{1}{2}\\\\\\=~\frac{2~.~(-4)~+~1~.~1}{2}\\\\\\=~\frac{-8+1}{2}\\\\\\=~\boxed{\frac{-7}{2}}

Resposta: Letra A

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