Question

Calcure as raízes e as coordenadas do vértice f (x) = 2x² - 12x + 10​

Answer 1

Resposta:

Raízes: 5 e 1

Vértice: V(3,-8)

Explicação passo-a-passo:

$2x^{2} -12x+10$

Cálculo do discriminante:

Δ=$b^{2} -4ac$

Δ=$(12)^2-4(2)(10)$

Δ=144-80

Δ=64

Calculando as raízes:

$\left \{ {{x_{1} =\frac{-b+\sqrt{delta} }{2a} } \atop {x_{2} =\frac{-b-\sqrt{delta} }{2a} }} \right.\\\\\left \{ {{x_{1} =\frac{12+8}{4} } \atop {x_{2} =\frac{12-8}{4} }} \right.\\\\\left \{ {{x_{1} =5} \atop {x_{2} =1}} \right.$

Cálculo do Vértice:

$V(\frac{-b}{2a} ,\frac{-delta}{4a})\\\\V(\frac{12}{4} ,\frac{-64}{8} )\\\\V(3,-8)$