Question

al x ² - 4 x+3=0 me ajude​

Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-4x+3=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-4~e~c=3\\\\\Delta=(b)^{2}-4(a)(c)=(-4)^{2}-4(1)(3)=16-(12)=4\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-4)-\sqrt{4}}{2(1)}=\frac{4-2}{2}=\frac{2}{2}=1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-4)+\sqrt{4}}{2(1)}=\frac{4+2}{2}=\frac{6}{2}=3\\\\S=\{1,~3\}$

Answer 2

Resposta:

A resposta no meu deu X1= 3 e X2=1.