Question

y*2-8y+15 fatore os polinômios​

Answer 1

Resposta:

y²-8y+15=(y-3)(y-5)

Explicação passo-a-passo:

$\displaystyle~Aplicando~a~f\'{o}rmula~de~Bhaskara~para~y^{2}-8y+15=0~~\\e~comparando~com~(a)y^{2}+(b)y+(c)=0,~temos~a=1{;}~b=-8~e~c=15\\\\\Delta=(b)^{2}-4(a)(c)=(-8)^{2}-4(1)(15)=64-(60)=4\\\\y^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-8)-\sqrt{4}}{2(1)}=\frac{8-2}{2}=\frac{6}{2}=3\\\\y^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-8)+\sqrt{4}}{2(1)}=\frac{8+2}{2}=\frac{10}{2}=5$

y²-8y+15=(y-y')(y-y")=(y-3)(y-5)