Question

- x ao quadrado-8×-12​

Answer 1

Explicação passo-a-passo:

x² - 8x +12=0

a=1

b=-8

c=12

Delta -> b² -4ac

(-8)² - 4.1.12

64 - 48 

Delta é igual á 16

valor de x:

x= -b+- (mais ou menos) √delta/2a

x= 8 +- √16/2.1

x= 8+- 4/2

x'= 8 + 4/2 -> x' = 12/2  -> x'= 6

x''= 8-4/2  -> x''= 4/2  -> x''= 2

Answer 2

Resposta:

Explicação passo-a-passo:

-x²-8x-12=0      ×(-1)

x²+8x+12=0

$\displaystyle~Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+8x+12=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=8~e~c=12\\\\\Delta=(b)^{2}-4(a)(c)=(8)^{2}-4(1)(12)=64-(48)=16\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(8)-\sqrt{16}}{2(1)}=\frac{-8-4}{2}=\frac{-12}{2}=-6\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(8)+\sqrt{16}}{2(1)}=\frac{-8+4}{2}=\frac{-4}{2}=-2\\\\S=\{-6,~-2\}$