Question

y= -x²+36 determine as coordenadas do vértice da parábola me ajudem pfvvvb​

Answer 1

Resposta:

a) y= -x²+36 a= -1 / b= 0/ c= 36

Xv= -b

----

2a

Xv= -(0)

-------

2(-1)

Xv= 0

--

-2

Xv=0

Yv= -∆ ∆=b²-4ac

---- ∆=0²-4.-1.36

4a ∆= 0+144

∆= 144

Yv= -(144)

---------

4.(-1)

Yv= -144

------

-4

Yv= 36

V(X,Y) = ( 0, 36)