Question

resolva as equaçoes de 2 grau -x²+6x-5=0

Answer 1

$- x^{2} + 6x -5 = 0 \\ \\Baskhara = \frac{-b+- \sqrt{ b^{2}-4.a.c }}{2.a}$

Primeiro calcule o delta :
$Delta = b^{2} -4.a.c \\ Delta = 36 .(-4.-1). -5 \\ Delta = 36 - 20 \\ Delta = 16 \\ \sqrt{16} = 4$

Agora jogue na fórmula de báskara :

$\frac{-b+- \sqrt{Delta} }{2.a} \\ \\ \frac{-6+-4}{-2} \\ \\ X1= 1 \\ X2 = 5$