Question

Gente me ajudem pfvr

Answer 1

${x}^{2} = 9.15 \\ x = \sqrt{9.15} \\ x = 3 \sqrt{15} cm$

${y}^{2} = (15 + 9).9 \\ {y}^{2} = 24.9 \\ {y}^{2} = {2}^{2} .2.3. {3}^{2} \\ y = \sqrt{ {2}^{2}.2.3. {3}^{2} } \\ y = 6 \sqrt{6}cm$