Question

Explique as propriedades do logaritmo tendo : log7=0,84 log5=0,70 é log2=0,30

A- logo 28






B- Log35





C- log700

Answer 1

Resposta:

A)

$log(28) = log(2 \times 2 \times 7) = log(2) + log(2) + log(7) = 0.30 + 0.30 + 0.70 = 1.30$

B)

$log(35) = log(7 \times 5) = log(7) + log(5) = .084 + 0.70 = 1.54$

C)

$log(700) = log(7 \times 100) = log(7) + log(100) = 0.84 + 2 = 2.84$