Question

Calcule o lim
6x  30
x5 x
2
25

Answer 1

Temos que

$\displaystyle\lim_{x \to 5} \frac{6x - 30}{ {x}^{2} - 25 } = \displaystyle\lim_{x \to 5} \frac{6(x - 5)}{ (x - 5)(x + 5) } \\ = \displaystyle\lim_{x \to 5} \frac{6}{ x + 5 } = \frac{6}{5 + 5} = \frac{6}{10} = \frac{3}{5}$