• Matéria: Matemática
  • Autor: lenyjacobina
  • Perguntado 9 anos atrás

Galerinha me ajudem nestas questões , é para amanhã !

Anexos:

Respostas

respondido por: deividsilva784
1
Log 1 + log Raiz de 128=
2 raiz de 2

Todo logaritmando igual a 1. É zero! Então fica.

0 + log 2^7/2 Fatorando 128. fica 2^7/2
2^1/2 raiz de 2. É o msm q 2^1/2


( 2^1/2)^x = 2^7/2
2^x/2 = 2^7/2
x/2 = 7/2
x= 7

b) 2. log 9 - log 2
9 128

Todo log do mesmo número é igual a 1
2 . 1 - log 2 =
128

2 - 128^× = 2
2 - 2^7x = 2
2 - 7x = 1
-7x = 1 - 2
-7x = -1 (-1)
x = 1/7

c) -3. log 1 + 6log 1 -7log 1
5 8 4
-3 . 0 + 6 . 0 + (-7). 0=
0

d) 1/2 .log128 -3/2.log 7
4 49
1/2. log 2^7 -3/2. log 7
4 49
1/2.( 7 log 2 - log 7^3/2
4 49

1/2. ( 7. 2 - ( 49^x = 7^3/2)
1/2. 7/2 -( 7^2.x = 7^3/2)
7/4 - (7^2x = 7^3/2)
7/4 -( 2x = 3/2)
7/4 -( x = 3/2 . 1/2)
7/4 -( x= 3/4)
7/4 -3/4=
4/4 = 1

4)

a) N= 3. log 8 -- 2/5. log 5 + log 100
Raiz de 2 25 0,01

N= 3. log 2^3 - 2/5. 2 + log 100
2^1/2 10^-2

N= 3.( ( 2^1/2 )^x)= 2^3) -4/5 + (-2)
N= 3. ( x/2 ) = 3
N= 3. ( x = 6)
N= 3.6
N= 18

N= 3.log 2 -2/3. log 10 + 1/2. log 1/2
4 100 4

N= 3. 1/2 - log 10^ -2/3 + 1/2( 4^x= 1/2)
100

N= 3/2 - ( 100^x = 10^ -2/3) + 1/2( 2^2x= 2^-1

N= 3/2 - 10^2x = 10^-2/3) + 1/2( 2x = -1)
N= 3/2 - ( 2x = -2/3) + 1/2( x= -1/2)
N= 3/2 -( x= -2/3 . 1/2) + 1/2 -1/2
N= 3/2 -( -2/6) + 0
N= 3/2 + 2/6
N= 11/6



c) N= 3/5. log3/2 -0,2.log 0.01
9/4 0,1

N= 3/5. ( 9/4^x = 3/2) -0.2 .log 100/10
0,1

N= 3/5( 3^2/2/2)^x = 3/2)) -0.2.(log 100 - log10
0,1 0,1

N= 3/5( 3/2)^2x= 3/2)) -0.2. ( (1/10)^x= 100 - ( 1/10)^x = 10

N= 3/5( 2x = 1) -0.2( 10^-1x = 10^2 -(10^-x = 10))

N= 3/5 ( x= 1/2) -0.2 ( -x = 2 (- x = 10))

N= 3/5 . 1/2 ( -0.2 ( -2 (- 10)))

N= 3/10 ( -0.2. -12)
N= 3/10 ( -2/10 .12)
N= 3/10 ( -24/10)
N= 3/10 ( -12/5)
N= 3/10. -12/5
N= -36/50
N= -18/25
Perguntas similares