Question

determine o valor de n nas equações n!=56
( n-2)!​

Answer 1

n!

--------- = 56

(n-2)!

n(n-1)(n-2)!

------------------- = 56

(n-2)!

n(n-1) = 56

n² - n - 56 = 0

∆=b² -4ac = 1² +224=225 => √∆=15

n' = -b+√∆/2a = 1+15/2 =16/2 = 8 ✓