Question

Simplifique:

$({2}^{n} + {2}^{n + 1} ) \times ( {3}^{n} + {3}^{n + 1} ) \div {6}^{n + 1}$
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Answer 1

Resposta:

2

Explicação passo-a-passo:

Temos que:

[2^n +2^(n+1)] . [3^n +3^(n+1)] / 6^(n+1)

[2^n + 2.2^n] . [3^n + 3.3^n] / [6.6^n]

(2^n).[1 + 2] . (3^n).[1 + 3] / [6.6^n]

3.(2^n) . 4.(3^n) / [6.6^n]

12.(2^n).(3^n) / [6.6^n]

2.(2^n).(3^n) / (6^n)

2.(2. 3)^n / (6^n)

2.(6^n) / (6^n)

2

Blz?

Abs :)