Question

calcule
$( \sqrt{ \sqrt{16} }) {}^{ - 4}$
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Answer 1

Resposta:

$( \sqrt{ \sqrt{16}^{ - 4} } = \\ \\ \sqrt{16 ^{ - 2} } = \\ \\ \sqrt[1]{16 ^{ - 1} } = \\ \\ {16}^{ - 1} = \\ \\ \frac{1}{16}$