Question

Qual é o segundo termo do desenvolvimento do binômio de Newton (2+a) elevado a 4?

Answer 1

(2+a)⁴ ==> n=4. p=2-1=1

T(P+1) = c(n,p). a^n-p. b^p

t(1+1) = c(4,1). 2⁴-¹. a¹

T2 = 4. 2³.a

T2 = 32a

Answer 2

Resposta:

T2= 32a

Explicação passo-a-passo:

$T_{p+1}=\left(\begin{array}{c}n&p\end{array}\right)a^{n-p}*b^{p}\\\\a=2\\b=a\\n=4\\p=1\\\\T_{1+1}=\left(\begin{array}{c}4&1\end{array}\right)2^{4-1}*a^{^{1}}\\\\T_{2}=4.2^{3} a\\\\T_{2}=32a\\\\\left(\begin{array}{c}4\\1\end{array}\right)=\frac{4}{1!.3!}=\frac{4.3!}{3!}=4$