Question

determine a solução de: -4x+6 (2-x) ≥ 0

Answer 1

Resposta:

$S=\{x\,\in\,\mathbb{R}\,|\,x\leqslant\frac{6}{5}\}$

Explicação passo-a-passo:

$- 4x + 6(2 - x) \geqslant 0 \\ - 4x + 12 - 6x \geqslant 0 \\ - 4x - 6x \geqslant - 12 \\ - 10x \geqslant - 12 \\ 10x \leqslant 12 \\ 5x \leqslant 6 \\ x \leqslant \frac{6}{5}$