Question

dada a funçao f(x)=3x^2-2x+6 calcule A) f(1/2), B) f(-3) C)f (0) , D)f (-4)

Answer 1

y= 3x²-2x+6

f(1/2)= 3(1/2)² - 2 (1/2) +6

f(1/2)= 3/4 -1+6

f(1/2)= 3/4+5 (mmc=4)

f(1/2)= 3/4+20/4

f(1/2)= 23/4

f(-3)= 3(-3)²-2(-3)+6

f(-3)= 27+ 6+6

f(-3)=39

f(0)=3(0)-2(0)+6

f(0)=6

f(-4)=3(-4)²-2(-4)+6

f(-4)=48+8+6

f(-4)=62