Question

Resolver em R: log3 (2x-1)= log3 5

Resolver em R: log (x2-2x)= log (x+10)

Answer 1

log3 (2x-1)= log3 5

(2x-1)= 5

2x=6

x=3 ✓

log (x2-2x)= log (x+10)

(x²-2x) = (x+10)

x² -3x -10 = 0

∆= 9+40=49 => √∆=7

x'=3+7/2=5 ✓

x"=3-7/2= -2 ✓