Question

A ) Log5 x = log5 16 B) logx (2x-3)= logx (-4x+8)

Answer 1

A)

$\log_5x = \log_5 16\\x=16$

B)

$\log_x(2x-3)=\log_x(-4x+8)\\2x-3=-4x+8\\2x+4x=8+3\\6x=11\\\\x=\frac{11}{6}$