Question

hipotenusa √26 catetos √16 e X​

Answer 1

${ \sqrt{26} }^{2} = { \sqrt{16} }^{2} + x$

$\sqrt{26.26} = \sqrt{16 +.16} + x$

$26 = 16 + x \\ x = 26 - 16 \\ x = 10$