Question

me Ajudem por favor

(A) X²-13x+32=0
(B) -x²+10×+25=0
(C) 7x²-1x-1=0
(D) x²-11x+10=0
(E)-x².x+5x-8=0
(F)6x²-x-2=0​

Answer 1

Resposta:

Obs: onde está escrito +ou- , lembra-se de substituir pelo sinal ±. As regras dizem que tem quer ser rtudo digitado e não consegui encontrar o simbolo,  

(A) X²-13x+32=0

$x=\frac{-(-13) +ou-\sqrt{(-13)^{2}-4.1.32 } }{2.1} \\x= \frac{13+ou-\sqrt{169-128} }{2} \\x=\frac{13+ou-\sqrt{41} }{2} \\x=\frac{13+\sqrt{41} }{2} \\x=\frac{13-\sqrt{41} }{2} \\x^{1}=\frac{13-\sqrt{41} }{2},x^{2} =\frac{13+\sqrt{41} }{2}$

Formula Alternativa: x¹≈ 3,29844  x²≈  9,70156

(B) ) -x²+10×+25=0

-$-x^{2} +10x+25=0\\x^{2} -10x-25=0\\x=\frac{- (-10) + ou -\sqrt{(-10)^{2}-4.1.(-25) } }{y} \\x=\frac{10+ ou -\sqrt{100+100} }{2} \\x=\frac{10+ ou - \sqrt{200}  }{2} \\x=\frac{10+10 \sqrt{2}  }{2} \\x=\frac{10-10 \sqrt{2}  }{2} \\x=5+5\sqrt{2} \\x=5-5\sqrt{2} \\x^{1} = 5-5\sqrt{2} ,x^{2}=  5+5\sqrt{2}$

Formula Alternativa: x¹≈  2,07107   x²≈ 1207107

(C) 7x²-1x-1=0

$7x^{2} -x-1=0\\x=\frac{-(-1)+ou-\sqrt{(-1)^{2}-4.7.(-1)} }{2.7} \\x= \frac{1+ou-\sqrt{1+28} }{14} \\x= \frac{1 +ou-\sqrt{29} }{14} \\x= \frac{1 +\sqrt{29} }{14} \\x= \frac{1 -\sqrt{29} }{14} \\x^{1} = \frac{1 -\sqrt{29} }{14} , x^{2} = \frac{1 +\sqrt{29} }{14}$

Formula Alternativa: x¹≈  0,313226   x²≈ 0,56083

(D) x²-11x+10=0

$x^{2} -x-10x+10=0\\x.(x-1)-10(x-1)=0\\(x-1).(x-10)=110\\x-1=0\\x-10=0\\x=1\\x=10\\x^{1} =1 ,x^{2} =10$

Formula Alternativa: x¹≈ 1  x²≈ 10

(E)-x².x+5x-8=0

Falso/errada

(F)6x²-x-2=0​

$6x^{2} +3x-4x-2=0\\3x.(x+1)-2(2+1)=0\\2x+1=0\\3x-2=0\\x= -\frac{1}{2} \\x= \frac{2}{3} \\x^{1} =\frac{1}{2} ,x^{2} =\frac{2}{3}$

Formula Alternativa: x¹≈ 0,5   x²≈ 0,666667