Question

utilize qualquer método para resolver o sistema 2m+ n =11
                                                                    4m -3n = 17

Answer 1

2m+ n =11 >>>n = 11 - 2m
4m -3n = 17
Substitui na segunda :
4m -3n = 17
4m -3(11 - 2m) = 17
4m -33 + 6m = 17
10m = 33 + 17
10m = 50
m = 5
n = 11 - 2m = 11 - 2*5 = 11 - 10 = 1
n = 1

Answer 2

$\left \{ {{2m+n=11~(4)} \atop {4m-3n=17(-2)}} \right. \\ \\ \left \{ {{8m+4n=44} \atop {-8m+6n=-34}} \right. \\ \\10n=10\\n=10\div10\\\boxed{n=1}\\ \\2m+n=11\\ \\m= \frac{11-n}{2}\\ \\m= \frac{11-1}{2} \\ \\\boxed{m=5}$