Question

xao quadrado -8x+12=0?

Answer 1

$x^{2} -8x+12=0\\ \\\\a=1;b=-8;c=12\\\\\\ \Delta=b^2-4ac\to \Delta=(-8)^2-4*1*12\to \Delta=64-48\to \Delta=16\\\\\\ x= \frac{-b+- \sqrt{\Delta} }{2a} \to x= \frac{-(-8)+- \sqrt{16} }{2*1} \to x= \frac{8+- 4}{2} \to \\\\\\ x'= \frac{8+ 4}{2} \to x'= \frac{12}{2} \to x'=6\\ \\\\x''= \frac{8-4}{2} \to x''= \frac{4}{2} \to x''=2\\\\\\ S=(2;6)$

Answer 2

x² - 8x + 12 = 0

a = 1
b = -8
c = 12

Delta:
Δ = b² - 4ac
Δ = (-8)² - 4 * 1 * 12
Δ = 64 - 48
Δ = 16
       Bhaskara:
       x = - b ± √Δ / 2a
       x = - (-8) ± √16 / 2 * 1
       x = 8 ± 4 / 2
       x' = 8 - 4 / 2 = 4 / 2 = 2
       x'' = 8 + 4 / 2 = 12 / 2 = 6

Espero ter ajudado. Valeu!