Question

na figura o triangulo ABC é isosceles de base Bc=5 E AC=6, qual equaçao geral da reta
aB?

Answer 1

isósceles --> 2 lados congruentes
base (BC) = 5
lado (AC) = 6
r(AB) = ...

Supondo o ponto B = 0
BC = 6 --> xC = 6, yC = 0
C (6,0)
B (0,0)
M(BC) = 5/2
h² = 5² - (5/2)²
h² = 25 - 25/4
4h² = 100 - 25
4h² = 75
h² = 75/4
h² = 25.3/4
h = √(25.3)/4
h = 5√3/4
A = 5√3/4
AB --> A (5/2, 5√3/4) --> B (0,0)
a = Δy / Δx
a = (0 - 5/2) / ( 0 - 5√3/4)
a = (-5/2) / (-5√3/4)
a = 5/2 x 4/5√3
a = 1/2 x 4/√3
a = 4/2√3
a = 4√3/2√3√3
a = 4√3 / 2.3
a = 4√3 / 6
a = 2√3 / 3