Question

considere a função f:IR⇒IR , tal que f(x) = -5x+1.O valor de f(-1) + f(1) +f(0) é:
A)1
B)-3
C) 3
D)5
E) -2

Answer 1

f(x)=-5x+1
f(-1)=-5(-1)+1
f(-1)=5+1
f(-1)=6

f(1)=-5*1+1
f(1)=-4+1
f(1)=-3

f(0)=-5*0+1
f(0)=1
Então
f(-1)+f(1)+f(0)=
6+(-3)+1
3+1=
4