Question

o numero complexo z= i^100 - i^50

Answer 1

100 /_4

(0) 25 ====> i¹°° = i^(0)= 1

50 /_4

(2). 12. ====> i^50 = i^(2)= -1

z= i^100 - i^50 =

z= 1 - (-1)= 1+1= 2 ✓