Question

alguém me ajudaaaaaa por favor ​

Answer 1

Resposta:

$x_1= 3\\\\x_2=2$

Explicação passo-a-passo:

$x^2 - 5x + 6 = 0\\\\\\x_{1\ y\ 2}= \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \qquad a=1\quad b=-5\quad c=6\\\\\\x_{1\ y\ 2}= \dfrac{-(-5)\pm\sqrt{(-5)^2-4(1)(6)}}{2(1)} x_{123} \\\\\\x_{1\ y\ 2}= \dfrac{+5\pm\sqrt{25-24}}{2}\\\\\\x_{1\ y\ 2}= \dfrac{+5\pm\sqrt{1}}{2}\\\\\\x_{1\ y\ 2}= \dfrac{+5\pm1}{2}\\\\\\x_{1}= \dfrac{+5+1}{2}\to x_1=\dfrac{6}{2}\to \bold{x=3} \\\\\\x_{2}= \dfrac{+5-1}{2}\to x_2=\dfrac{4}{2}\to \bold{x=2}$