Question

Interpole 200 termos entre 10 e 1206?

Answer 1

Resposta:

PA(10,16,22,28,34,...,1194,1200,1206)

Explicação passo-a-passo:

A1=10

A200=1206

n=200

r=?

An=A1+(n-1)r

1206=10+(200-1)r

1196=199r

r=1196/199~=6

r=6

PA(10,16,22,28,34,...,1194,1200,1206)