Question

sabendo que o valor do log2=0,3010 e log3=0,4771, calcule:
a)log9 b)log2‐¹​

Answer 1

a)

$log(9) = \\ log(3 \times 3) \\ log(3) + log(3) = \\ 0.4771 + 0.4771 = 0.9542$

b)

$log(2 ^{ - 1} ) = \\ log(1 \div 2) = \\ log(1) - log(2) = \\ 0 - 0.3010 = - 0.3010$