Question

5) Sendo log 2 = 0,3010; log 3 = 0,4771 e log 5 = 0,6990, Calcule os logaritmos usando as propriedades:
a) log 25
b) log3 12
c) log 15/4
d) log 5 elevado a 6​

Answer 1

sendo:

log(2) = 0.3010

log(3) = 0.4771

log(5) = 0.6990

a)

log(25) = log(5^2) = 2log(5) = 2*0.699 = 1.398

b)

log3(12) = log(12)/log(3)

= log(2*2*3)/log(3) = (2log(2) + log(3))/log(3)

= (2*0.3010 + 0.4771)/0.4771 = 2.2618

c)

log(15/4)  = log(3) + log(5) - log(4)

= 0.4771 + 0.6990 - 2*0.3010 = 0.5741

d)

log(5^6) = 6log(5) = 6*0.6990 = 4.194