Question

calcule as raízes da equação
$3 {x }^{2} + 4 x + 1 = 0$
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Answer 1

3x²+4x+1 = 0

Δ = b²-4ac

Δ = (4)² - 4(3)(1)

Δ = 16 - 12

Δ = 4

x = -b+-√Δ / 2a

x' = -4+2 / 6 = -2/6 = -1/3

x'' = -4-2 / 6 = -6/6 = -1