Question

valor das funções trigonométricas de:
a)-600°:

b)-8pi/3

Answer 1

600|360

-360 1

240

-600°=1.(-360)-240

-240°=120-360°

sen(-600°) =sen(120°)=√3/2

cos(-600°)=cos(120°) = -½

tg(-600)=tg(120°) = -√3

cossec(-600°) =cossec(120°) =2√3/3

sec(-600°) =sec(120°) = -2

Cotg(-600°) =cotg(120°) =-√3/3

b) (-8π/3)=(-6π/3-2π/3)=(-2π-2π/3)

-2π/3=4π/3-2π

sen(-8π/3)=sen(4π/3)= -√3/2

cos(-8π/3)=cos(4π/3)=-½

tg(-8π/3)=tg(4π/3)=√3

cossec(-8π/3)=cossec(4π/3)=-2√3/3

Sec(-8π/3)=sec(4π/3)=-2

cotg(-8π/3)=cotg(4π/3)=√3/3