Question

Calcule: Se log 2=0,30 e Log 3=0,48, calcule;
A)LOG 12
B)LOG 36
C)LOG 27
D)LOG 30

Answer 1

Resposta:

a)

$log(12) = \\ log(4 \times 3) = \\ log(4) + log(3) = \\ log( {2}^{2} ) + 0.48 = \\ 2 log(2) + 0.48 = \\ 2(0.30) + 0.48 = 1.08$

b)

$log(36) = \\ log(6 \times 6) = \\ log(6) + log(6) = \\ log(2 \times 3) + log(2 \times 3) = \\ log(2) + log(3) + log(2) log(3) = \\ 0.30 + 0.48 + 0.30 + 0.48 = 1 .56$

c)

$log(27) = \\ log( {3}^{3} ) = \\ 3 log(3) = \\3(0.48) = 1.44$

d)

$log(30) = \\ log(10 \times 3) = \\ log(10) + log(3) = \\ log(2 \times 5) + 0.48 = \\ log(2) + log(5) + 0.48 = \\ 0.30 + log(5) + 0.48 = 0.78 + log(5)$