Question

calcule a derivada f(x)=5x⁴-3x²+4x. dias 1 e 2​

Answer 1

f (x) = 5x⁴ -3x²+4x

f'(x) = 20x³ -6x +4

f'(1) = 20.1³ -6.1 +4 = 20 -6+4= 18

f'(2) = 20.2³ -6.2 +4 =160 -12+4= 152