Question

alguém?................

Answer 1

Resposta:

A) $\\A)cos30=\frac{x}{9}\\ \frac{\sqrt{3} }{2} =\frac{x}{9} \\x=9\frac{\sqrt{3} }{2} \\x=4,5\sqrt{3} \\\\sen30=\frac{y}{9}\\\frac{1}{2} =\frac{y}{9} \\ y= 9* 1/2\\y= 4,5\\\\B)  sen 60=x/6\sqrt{3}\\ \sqrt3}/2 =x/6\sqrt{3}\\ 2x=6.\sqrt{3}.\sqrt{3} \\ x=\frac{6.\sqrt{9} }{2} \\x=3.3\\x=9\\cos60=\frac{y}{6\sqrt{3} }\\\frac{1}{2}=\frac{y}{6\sqrt{3} }\\   2y=6\sqrt{3}\\ y=\frac{6\sqrt{3} }{2} \\y=3\sqrt{3}$

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