Question

3x²-5x 2=0 Precisa aplicar bhaskara

Answer 1

delta = b^2 - 4*a*c

a=3 ; b=-5; c=2

(-5^2)- 4* 3 * 2
25-24
delta = 1

x' = -b+raizqDelta/2*a
x' = -(-5) + raizq1 / 2*3
x' = (5 + 1)/6
x' = 1

x'' = -b-raizqDelta/2*a
x'' = -(-5) - raizq1/2*a
x'' = (5-1)/6
x'' = 4/6
x'' = 2/3

Solução:
Raizes: 1 e 2/3