Question

Calcule a integral

 

∫(x³-3x²+senx)dx

Answer 1

$\int {(x^3-3x^2+senx)} \, dx =\int x^3-3 \int x^2+ \int senx= \\ \\ \frac{x^4}{4}-3\frac{x^3}{3}-cos x \\ \\ \frac{x^4}{4}-x^3-cosx + C$