Question

Como se reolve a euação literal:

$<var>x^{2}+ax-2a^{2}=0</var>$

Answer 1

$x^2+ax-2a^2=0 \\ \\ \Delta=a^2-4.1.(-2a^2)=a^2+8a^2=9a^2 \\ \\ x=\frac{-a+-\sqrt{9a^2}}{2}=\frac{-a+-3a}{2} \\ \\ x_1=\frac{-4a}{2}=-2a \\ \\ x_2=\frac{2a}{2}=a \\ \\ \boxed{\boxed{S= \{-2a,a \}}}$