Question

me ajudem nesse cálculo por favor ​

Answer 1

Resposta:

${( \frac{ \sqrt[3]{2} + 1}{ \sqrt[3]{3} } )}^{2} = {( \frac{ \sqrt[3]{2} + 1}{ \sqrt[3]{3} } )}.{( \frac{ \sqrt[3]{2} + 1}{ \sqrt[3]{3} } )} = \frac{( \sqrt[3]{2} + 1).( \sqrt[3]{2} + 1)}{ \sqrt[3]{3} . \sqrt[3]{3} } = \frac{ \sqrt[3]{4} + \sqrt[3]{2} + \sqrt[3]{2} + 1 }{ \sqrt[3]{9} } = \frac{ \sqrt[3]{4} + 2 \sqrt[3]{2} + 1}{ \sqrt[3]{9} } = \frac{(\sqrt[3]{4} + 2 \sqrt[3]{2} + 1). \sqrt[3]{ {9}^{2} } }{ \sqrt[3]{9} . \sqrt[3]{ {9}^{2} } } = \frac{ \sqrt[3]{324} + 2 \sqrt[3]{162} + \sqrt[3]{81} }{ \sqrt[3]{ {9}^{3} } } = \frac{ \sqrt[3]{324} + 2 \sqrt[3]{162} + \sqrt[3]{81} }{9}$