Question

.
$2 log32 -2 log8 + 2 log4$
​

Answer 1

Explicação passo-a-passo:

$= 2( log( 32) - log(8) + log(4) )$

$= 2( log(\frac{32}{8} ) - log(4) )$

$= 2( log(4) - log(4) )$

$= 2(0)$

$= 0$